... HM VAH , Atlanta VAC , Biloxi HM - A HM - A HM - A HM - B HM - B VAH , Cleveland 1st 3rd Place Place VAC , Ft . Harrison HM HM - A VAH , Ft . Howard HM ப VAC , Hines VAC , Hot Springs VAH , Iowa City HM HM - B 3rd Place - A HM - A ...

for every x ∈ Hm - r ( B ; G ) and that 2s = 0 if r is even . Since this result will be used only in the present ... ( B ) . By the exactness of Gysin's cohomology sequence , we deduce that the homo- morphism $ * : Hm - r - 1 ( B ) ...

... B , hm ( B ) , Хв , < B ) the transitive B B closure * of is Noetherian and confluent . Proof . It is sufficient to prove that for every term xek in hm ( U ) , there is a unique g ∈ Pr such that xek g and g∈ ( N ( hm ( U ) ) ) . B * Since ...

... B , hm ( B ) , Xß , < B ) defines a resolving decomposition of U. Indeed , it follows immediately by construction that the Conditions ( i ) , ( ii ) and ( iv ) are satisfied . The first part of Condition ( iii ) is a consequence of the ...

... hm ) of E. If Hm A , we are finished . Suppose that Hm A. Then we claim that hm ( Hm ) = B. For if not , there exist ã € A \ Hm and bЄ Bhm ( Hm ) . Let H Hm U { a } and define h : H → B by setting h ( a ) hm ( a ) for a Є Hm and h ...

... Hm } into { d1 , ... , dm } such that ... , dm } ( Hi , f ( Hi ) ) , 1 ≤ i ≤m are all the edges of T. Let us consider Am = { e , am , bm , cm } . ( Remember m ≥ 2. ) Assume first that Am is of type 1 and define the elements dm.c , dm , b ...

... b ( 3 ) 1513-15 With AN . c ( 1 ) n.d. With ornament B ( 1 ) 1488 , 1504 With stamp 1042 : 1500 ( 3 ) London With HM . b ( 3 ) [ F.D. ] 1596 With RC . a ( 1 ) 1596 With HE . d ( 1 ) 1596 FC . b SPIRAL ( 1 ) Alone 1506 With stamp 1043 ...

George W. Whitehead. q Hm ( B ; G1 ) Hm ( B ; Go ) Hm + 1 ( B ; Go ) Hm + 2 ( B ; G。) Figure 13.4 we have the short exact sequence 0 → Jm + 1 , 1 → Ĝm + 2 ( B ) → Em + Combining these two sequences with - 0 Ker d2 → 0 . - > 0 → Ker d2 → Hm ...

... HM ( B ) x JM ( R ) / HM ( B ) - C % . Proof : The commutator group [ JM ( B ) , JM ( R ) ] lies in HM ( B ) . Moreover , since Jm ( ) normalises 0 , the subgroup Ker ( 0 ) is a normal subgroup of JM ( B ) , and HM ( B ) / Ker ( 0 ) ...

... hm ) c = 1 , d = - 9 b = R + h ( 1 + hm / 2 ) R + h / 2 ( 12.23 ) Emhm ( 1 − v ) 2E — The membrane strains of the top and bottom layers as well as the shear strain of the middle layer become d cosh √ã ( b2 + ã2 ) + ā2 ) ( px / īm ) ...